How do we find the value of $x$ where the tangent line to $f(x

#1 Find the points on the lemniscate where the tangent is horizontal. 8(x2 + y2)2 = 25(x2 − y2) I got the derivative is y' (x) = (x (-16 x^2-16 y^2+25))/ (y (16 x^2+16 y^2+25)) and
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Finding the Points at which the Tangent Line is Horizontal f(x

Enter the equation of curve to find horizontal tangent line. Horizontal Tangent line calculator finds the equation of the tangent line to a given curve. Step 2: Click the blue arrow to submit.

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